Steven Howe wrote: > MRAB wrote: >> On May 16, 4:21 pm, Lisa <[EMAIL PROTECTED]> <mailto:[EMAIL PROTECTED]> >> wrote: >> >> I am reading in data from a text file. I want to enter each value on >> the line into a list and retain the order of the elements. The number >> of elements and spacing between them varies, but a typical line looks >> like: >> >> ' SRCPARAM 1 6.35e-07 15.00 340.00 1.10 3.0 ' >> > Using builtin functions: > > ax = ' SRCPARAM 1 6.35e-07 15.00 340.00 1.10 3.0 ' > >>> ax.replace(' ','') # replace all double spaces with nothing > ' SRCPARAM 1 6.35e-07 15.00340.00 1.103.0 ' > >>> ax.replace(' ','').strip() # strip leading/trailing white spaces > 'SRCPARAM 1 6.35e-07 15.00340.00 1.103.0' > >>> ax.replace(' ','').strip().split(' ') # split string into a > list, using remaining white space as key > ['SRCPARAM', '1', '6.35e-07', '15.00340.00', '1.103.0'] > > def getElements( str ): > return str.replace( ' ', '' ).strip().split(' ') > > > sph > Made a mistake in the above code. Works well so long as there are no double spaces in the initial string. Try 2: def compact( y ): if y.find(' ') == -1: return y else: y = y.replace( ' ', ' ' ) return compact( y )
>>> ax = ' acicd 1.345 aex a;dae ' >>> print compact( ax ) acicd 1.345 aex a;dae >>> print compact( ax ).strip().split() ['acicd', '1.345', 'aex', 'a;dae'] sph > -- > HEX: 09 F9 11 02 9D 74 E3 5B D8 41 56 C5 63 56 88 C0 > -- HEX: 09 F9 11 02 9D 74 E3 5B D8 41 56 C5 63 56 88 C0 -- http://mail.python.org/mailman/listinfo/python-list
