On May 18, 12:06 am, [EMAIL PROTECTED] wrote:
> Hi,
> I am parsing an xml file ,before that i have replaced a string in
> the original xml file with another and made a new xml file which will
> now be parsed.I am also opening some more files for output.The
> following code shows some i/o commands.
> file_input = raw_input("Enter The ODX File Path:")
> input_xml = open(file_input,'r')
>
> (shortname,ext)=os.path.splitext(file_input)
> f_open_out=shortname+".ini"
> log=shortname+".xls"
> test_file=shortname+"testxml.xml"
>
> saveout = sys.stdout
>
> xmlcont=input_xml.read()
> input_xml.close()
>
> xmlcont=xmlcont.replace('localId','dataPackageId')
>
> output_file = open(test_file,"w")
> output_file.write(xmlcont)
> output_file.close()
>
> f_open=open(f_open_out, 'w')
> logfile=open(log,"w")
> sys.stdout = f_open
>
> After this i have to parse the new xml file which is in
> output_file .hence
>
> input_xml_sec = open(output_file,'r')
> xmldoc = minidom.parse(input_xml_sec)
>
> But i am getting an error on this line
> (input_xml_sec = open(output_file,'r')).I have tried to figure out
> but
> not able to debug.Can someone throw some light or anything they feel
> could be going wrong somewhere.
> How do i capture the error as it vanishes very
> qucikly when i run through command prompt,(the idle envir gives
> indentation errors for no reason(which runs perfectly from cmd
> prompt),hence i dont run using conventional F5.
http://docs.python.org/tut/
Read carefully.
--
http://mail.python.org/mailman/listinfo/python-list
