On May 17, 4:40 pm, Michael Bentley <[EMAIL PROTECTED]> wrote:
> On May 17, 2007, at 6:33 PM, Lyosha wrote:
>
> > Converting binary to base 10 is easy:
> >>>> int('11111111', 2)
> > 255
>
> > Converting base 10 number to hex or octal is easy:
> >>>> oct(100)
> > '0144'
> >>>> hex(100)
> > '0x64'
>
> > Is there an *easy* way to convert a number to binary?
>
> def to_base(number, base):
> 'converts base 10 integer to another base'
>
> number = int(number)
> base = int(base)
> if base < 2 or base > 36:
> raise ValueError, "Base must be between 2 and 36"
> if not number:
> return 0
>
> symbols = string.digits + string.lowercase[:26]
> answer = []
> while number:
> number, remainder = divmod(number, base)
> answer.append(symbols[remainder])
> return ''.join(reversed(answer))
>
> Hope this helps,
> Michael
That's way too complicated... Is there any way to convert it to a one-
liner so that I can remember it? Mine is quite ugly:
"".join(str((n/base**i) % base) for i in range(20) if n>=base**i)
[::-1].zfill(1)
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