Steve Holden a écrit :
> i3dmaster wrote:
>> On May 16, 1:05 pm, Steve Holden <[EMAIL PROTECTED]> wrote:
>>> Martin Blume wrote:
>>>> "tmp123" schrieb >
>>>>> We have very big files with python commands
>>>>> (more or less, 500000 commands each file).
>>>>> It is possible to execute them command by command,
>>>> inp = open(cmd_file)
>>>> for line in inp:
>>>> exec line
>>> The problem with this approach is that each line executes without any
>>> connection to the environment created by previous lies.
>>>
>>> Try it on a file that reads something like
>>>
>>> xxx = 42
>>> print xxx
>>>
>> cat file:
>>
>> x = 100
>> print x
>>
>> cat file.py:
>> #!/usr/bin/python2.4
>>
>> import os.path
>> import sys
>>
>> file, ext = os.path.splitext(sys.argv[0])
>> f = open(file,'rb')
>> for i in f:
>> exec i
>>
>>> ./file.py
>> 100
>>
>> Don't see the problem though.
>>
> No, because there isn't one. Now try adding a function definition and
> see how well it works.
>
> regards
> Steve
This is just a problem with indentation and blocks of code, the
followong will do :
commands = open("commands")
namespace, block = {}, ""
for line in commands :
line=line[:-1]
if not line : continue
if line[0].isspace() :
block += '\n' + line
continue
else :
if block.strip() :
exec block in namespace
block = line
exec block in namespace
print dict((k, v) for k, v in namespace.items() if k != "__builtins__")
with commands containing :
"""
x = 5
def toto(arg) :
print arg
def inner() :
print arg*arg
inner()
toto(x)
"""
output :
5
25
{'x': 5, 'toto': <function toto at 0x01D30C70>}
(sorry Steve for the private mail)
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