On May 11, 2:28 pm, [EMAIL PROTECTED] wrote:
>
>
>
>
>
> > Hello all,
>
> > First let me appologise if this has been answered but I could not find
> > an acurate answer to this interesting problem.
>
> > If the following is true:
> > C:\Python25\rg.py>python
> > Python 2.5.1 (r251:54863, Apr 18 2007, 08:51:08) [MSC v.1310 32
> > bit (Intel)] on
> > win32
> > Type "help", "copyright", "credits" or "license" for more
> > information.
> > >>> [] == []
> > True
> > >>> ['-o'] == []
> > False
> > >>> ['-o'] == False
> > False
>
> > Then why do I get the following results:
> > C:\Python25\rg.py>help.py -o
> > print arg ['-o']
> > type(arg): <type 'list'>
> > arg is True? False
> > help.py version 1.0 Copyright RDEG (c) 2007
> > ['-o'] is an unrecognized option.
> > Progam Exit (0)
>
> > <python>
> > import sys
>
> > _ver_ = 1.00
>
> > if '-h' in sys.argv or '--help' in sys.argv:
> > print
> > print " help.py Version", _ver_, "Copyright RDEG (c) 2007"
> > print '''
>
> > Options : -h, --help -- display this message
> > Progam Exit (0)'''
> > sys.exit(0)
> > else:
> > arg = sys.argv[1:]
> > print 'print arg', arg
> > print 'type(arg):', type(arg)
> > print 'arg is True?', arg == True
> > print " help.py version", _ver_, "Copyright RDEG (c) 2007"
> > print " ", arg, "is an unrecognized option."
> > print " Progam Exit (0)"
> > sys.exit(0)
> > </python>
>
I hope this helps (I have tried to post this twice already but it
seems to be going somewhere else) you help me.
What I would like to happen is:
else:
arg = sys.argv[1:]
print 'print arg', arg
print 'type(arg):', type(arg)
print 'arg is True?', arg == True
if arg != True:
print " No Option Provided"
print " help.py version", _ver_, "Copyright RDEG (c) 2007"
print " ", arg, "is an unrecognized option."
print " Progam Exit (0)"
sys.exit(0)
But as you can see by my output ['-o'] seems to be False as well as []
so the if happens regardless.
According to the "Book", ['-o'] should return True which should fail
the if, no?
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