Is it possible to call threads inside another thread (nested threads)? The example above creates a thread to call a function "eat" every time based on a specified interval. Now for example, if I make the called function "eat" to spawn threads to do the work in a queue and when all jobs are done, spawned threads join. When the next interval is up this process repeat itself.
Thanks. On May 7, 11:19 pm, Nick Vatamaniuc <[EMAIL PROTECTED]> wrote: > On May 7, 10:42 pm, Nick Vatamaniuc <[EMAIL PROTECTED]> wrote: > > > > > On May 7, 10:07 pm, johnny <[EMAIL PROTECTED]> wrote: > > > > Is there a way to call a function on a specified interval(seconds, > > > milliseconds) every time, like polling user defined method? > > > > Thanks. > > > Sure, > > > >>> def baz(): > > > ...: print "Baz!" > > ...: > > > >>> from threading import Timer > > >>> timer=Timer(5.0,baz) > > >>> timer.start() > > >>> Baz! > > > Cheers, > > -Nick Vatamaniuc > > By the way, here is another way to do it. This way it will repeat, the > other one executed once. Of course, if it executed once, you can make > it do it again, but there is some trickery involved. Here is a way to > do it using threads. > > Hope it helps, > -Nick Vatamaniuc > > from threading import Thread > from time import sleep > > class Repeater(Thread): > def __init__(self,interval,fun,*args,**kw): > Thread.__init__(self) > self.interval=interval > self.fun=fun > self.args=args > self.kw=kw > self.keep_going=True > > def run(self): > while(self.keep_going): > sleep(self.interval) > self.fun(*self.args,**self.kw) > > def stop_repeating(self): > self.keep_going=False > > def eat(*a): > print "eating: " , ','.join([stuff for stuff in a]) > > r=Repeater(1.0, eat, 'eggs','spam','kelp') > r.start() > sleep(6.0) > r.stop_repeating() -- http://mail.python.org/mailman/listinfo/python-list
