On May 4, 12:39 pm, 7stud <[EMAIL PROTECTED]> wrote: > On May 4, 3:30 pm, [EMAIL PROTECTED] wrote: > > > > > Hi, > > > Can anyone explain the following: > > > Python 2.5 (r25:51908, Apr 9 2007, 11:27:23) > > [GCC 4.1.1 20060525 (Red Hat 4.1.1-1)] on linux2 > > Type "help", "copyright", "credits" or "license" for more information.>>> > > def foo(): > > > ... x = 2 > > ...>>> foo() > > >>> def bar(): > > > ... x[2] = 2 > > ... > > > >>> bar() > > > Traceback (most recent call last): > > File "<stdin>", line 1, in <module> > > File "<stdin>", line 2, in bar > > NameError: global name 'x' is not defined > > > Thanks, > > Jianbing > > The first function is completely irrelevant unless you expect this to > work: > > x = 2 > x[2] = 2 > > Traceback (most recent call last): > File "test1.py", line 2, in ? > x[2] = 2 > TypeError: object does not support item assignment > > So that leaves you with: > > > >>> def bar(): > > > ... x[2] = 2 > > ... > > > >>> bar() > > Would you expect this to work: > > x[2] = 2 > print x
I will sympathize with the OP to the extent that the message "global name 'x' is not defined" is a bit misleading. All that the interpreter really knows is that 'x' is not defined, locally or globally, and it should probably not presume to guess the coder's intention. -- http://mail.python.org/mailman/listinfo/python-list
