On May 2, 7:47 am, Tim Golden <[EMAIL PROTECTED]> wrote: > Robert Rawlins - Think Blue wrote: > > > I'm trying to open a file using open() but the name of the file is created > > dynamically as a variable, but also has part of a static path. For instance, > > the file may be called 'dave' and will always be in '/my/files/here/'. > > Well that's an absolutely normal way of doing > things, so if my toy example below doesn't make > things clear, you'd better post a code fragment > and/or some traceback. > > <code> > import os, sys > > path = "c:/temp" > for filename in ["chas.txt", "dave.txt"]: > f = open (os.path.join (path, filename)) > print filename > print f.read () > print > f.close () > > </code> > > TJG
you have to look at the method open(string path, string mode) properties so, you can change the argument, string path, dynamicly -- http://mail.python.org/mailman/listinfo/python-list
