Hi, I am using Windows + Python 2.5.
This line of code fails (see error message at the end), last_line = subprocess.Popen(["D:/release/win.exe 0.5 1000 100 D:/ images/img.ppm out.ppm"], stdout=subprocess.PIPE).communicate()[0] but using "os.system" works: os.system('D:/release/win.exe 0.5 1000 100 D:/images/img.ppm out.ppm') ---------- C:/Python25/pythonw.exe -u "D:/run.pyw" Traceback (most recent call last): File "D:/run.pyw", line 59, in <module> process_dir(mydir) File "D:/run.pyw", line 52, in process_dir segmentation (dir,f) File "D:/run.pyw", line 35, in segmentation last_line = subprocess.Popen(["D:/release/win.exe 0.5 1000 100 D:/ images/img.ppm out.ppm"], stdout=subprocess.PIPE).communicate()[0] File "C:\Python25\lib\subprocess.py", line 593, in __init__ errread, errwrite) File "C:\Python25\lib\subprocess.py", line 793, in _execute_child startupinfo) WindowsError: [Error 22] The filename, directory name, or volume label syntax is incorrect ----------- Can anyone tell me why? Thanks bahoo -- http://mail.python.org/mailman/listinfo/python-list