IamIan <[EMAIL PROTECTED]> wrote in
news:[EMAIL PROTECTED]:
> Thank you again for the great suggestions. I have one final
> question about creating a httpMonths dictionary like {'Jan':'01'
> , 'Feb':'02' , etc} with a minimal amount of typing. My code
> follows (using Python 2.3.4):
>
> import calendar
>
> # Create years list, formatting as strings
> years = map(str, xrange(1990,2051))
>
> # Create months list with three letter abbreviations
> months = list(calendar.month_abbr)
>
> # Create monthTotals dictionary with default value of zero
> monthTotals = dict.fromkeys(months[1:],0)
>
> # Create yearTotals dictionary with years for keys
> # and copies of the monthTotals dictionary for values
> yearTotals = dict([(year, monthTotals.copy()) for year in
> years])
>
> # Create httpMonths dictionary to map month abbreviations
> # to Apache numeric month representations
> httpMonths =
> {"Jan":"01","Feb":"02","Mar":"03","Apr":"04","May":"05","Jun":"0
6
> ","Jul":"07","Aug":"08","Sep":"09","Oct":"10","Nov":"11","Dec":"
1
> 2"}
>
> It is this last step I'm referring to. I got close with:
> httpMonths = {}
> for month in months[1:]:
> httpMonths[month] = str(len(httpMonths)+1)
>
> but the month numbers are missing the leading zero for 01-09.
> Thanks!
>
Maybe something like:
httpMonths = dict((k,"%02d" % (x+1))
for x,k in enumerate(months[1:]) )
--
rzed
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