On 4/20/07, Steven W. Orr <[EMAIL PROTECTED]> wrote: > I really tried. I give up. > > Now I want something that's going to give me a string whose value is the > set of all of the first letters of months. Order is not important.
>>> ''.join(set([s[0] for s in calendar.month_abbr[1:]])) 'ADFJMONS' > And for extra credit, I need the string whose value is the set of all of > the letters of months minus the first letter. I'm sure there must be a cleaner way to do this, but it works: >>> ''.join(set(''.join([s[1:] for s in calendar.month_abbr[1:]]))) 'acbeglonprutvy' > E.g., 'ADFJMONS', 'acbeglonprutvy' -- Jerry -- http://mail.python.org/mailman/listinfo/python-list