[EMAIL PROTECTED] wrote:
> On Apr 19, 2:39 pm, Steve Holden <[EMAIL PROTECTED]> wrote:
>> [EMAIL PROTECTED] wrote:
>>> Hi,
>>> I have the following code which send/receive HTTP request/response:
>>> # where sampleUrl is '127.0.0.1' and
>>> # url is 'www.cnn.com'
>>> h = httplib.HTTP(self.sampleUrl, 8080)
>>> h.putrequest('GET', '/sample?url=' + self.url)
>>> h.endheaders()
>>> errcode, errmsg, headers = h.getreply()
>>> But it never returns from h.getreply().
>>> I am using python 2.3.4. Can you please tell me what am I missing?
>>> I am sure the url is correctly. I try putting this 'http://
>>> 127.0.0.1:8080/sample?url=www.cnn.com'and it works.
>>> Thank you for any help.
>[...]
>>
>> For what it's worth you *do* appear to have formed the calls correctly,
>> so something a little more complex is going on here.
>>
>> You might consider using WireShark (nee Ethereal) to look at the data
>> passing across the wire when you use the browser and when you use
>> httplib then comparing the data. That won't work on Windows because it
>> disobligingly refuses to let you tap into the loopback (127) network.
>>
>> regards
>> Steve
>
>
> Thanks. I run the same script hits the same server (a tomcat server):
> One is on Fedora 5 with python 2.4, this works.
> But one is on Red Hat 4 with python 2.3, this one does not work.
>
> Can you please tell me how can I make the script works on RHEL 4
> without upgrading it to python 2.3?
>
I can't see anything in
http://svn.python.org/view/python/trunk/Lib/httplib.py?rev=54581&view=log
that screams it might have fixed a problem. But I'd be tempted to try
and "borrow" a copy of 2.4's httplib, run your program with that in a
directory where it will be found before the standard library 2.3 module
and see if it fixes the problem.
If so, would it be a usable workaround just to use the 2.4 httplib for
that one program?
regards
Steve
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