On Apr 19, 3:37 pm, Anton Vredegoor <[EMAIL PROTECTED]> wrote:
> Anton Vredegoor wrote:
> > Maybe this one is better?
>
> No, this one keeps generating output.
>
> But this one stops at least:
>
> from collections import deque
> from itertools import chain, repeat
>
> def xsplitter(seq, pred):
> Q = deque(),deque()
> sentinel = object()
> it = chain(seq,repeat(sentinel))
> def gen(p):
> for x in it:
> if x is sentinel:
> while Q[p]: yield Q[p].popleft()
> break
> elif pred(x) == p:
> while Q[p]: yield Q[p].popleft()
> yield x
> else:
> Q[~p].append(x)
> for x in gen(p): yield x
> return gen(1),gen(0)
>
> def test():
> L = 1, 2, 3, 'a', 'a'
> # L = 'a', 1, 2, 'a'
> # L = 1, 'a', 3, 'a', 4, 5, 6, 'a'
> it1, it2 = xsplitter(L, lambda x: x == 'a')
> print it1.next()
> print it2.next()
> print it1.next()
> print it2.next()
>
> if __name__=='__main__':
> test()
>
> Are there any other cases this doesn't cover?
>
> A.
This one gets the order wrong. With
def test():
L = 1, 2, 3, 'a', 4, 'a', 5, 'a', 6, 'a'
it1, it2 = xsplitter(L, lambda x: x == 'a')
print it1.next()
print it2.next()
print it1.next()
print it2.next()
print it1.next()
print it2.next()
print it1.next()
print it2.next()
5 will appear before 4.
--
Regards,
Steven
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