On Apr 15, 9:49 pm, James Stroud <[EMAIL PROTECTED]> wrote:
> py> t = timeit.Timer(stmt=s)
> py> print "%.2f usec/pass" % (1000000 * t.timeit(number=100000)/100000)
> 40.88 usec/pass
>

What does this accomplish:

1000000 * t.timeit(number=100000)/100000

that the following doesn't accomplish:

10 * t.timeit(number=100000)

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