In <[EMAIL PROTECTED]>, Marko.Cain.23
wrote:
> On Apr 14, 10:36 am, [EMAIL PROTECTED] wrote:
>> On Apr 14, 12:02 am, Michael Bentley <[EMAIL PROTECTED]>
>> wrote:
>>
>>
>>
>> > On Apr 13, 2007, at 11:49 PM, [EMAIL PROTECTED] wrote:
>>
>> > > Hi,
>>
>> > > I have a list of url names like this, and I am trying to strip out the
>> > > domain name using the following code:
>>
>> > >http://www.cnn.com
>> > >www.yahoo.com
>> > >http://www.ebay.co.uk
>>
>> > > pattern = re.compile("http:\\\\(.*)\.(.*)", re.S)
>> > > match = re.findall(pattern, line)
>>
>> > > if (match):
>> > > s1, s2 = match[0]
>>
>> > > print s2
>>
>> > > but none of the site matched, can you please tell me what am i
>> > > missing?
>>
>> > change re.compile("http:\\\\(.*)\.(.*)", re.S) to re.compile("http:\/
>> > \/(.*)\.(.*)", re.S)
>>
>> Thanks. I try this:
>>
>> but when the 'line' ishttp://www.cnn.com, I get 's2' com,
>> but i want 'cnn.com' (everything after the first '.'), how can I do
>> that?
>>
>> pattern = re.compile("http:\/\/(.*)\.(.*)", re.S)
>>
>> match = re.findall(pattern, line)
>>
>> if (match):
>>
>> s1, s2 = match[0]
>>
>> print s2
>
> Can anyone please help me with my problem? I still can't solve it.
>
> Basically, I want to strip out the text after the first '.' in url
> address:
>
> http://www.cnn.com -> cnn.com
from urlparse import urlsplit
def get_domain(url):
net_location = urlsplit(url)[1]
return '.'.join(net_location.rsplit('.', 2)[-2:])
def main():
print get_domain('http://www.cnn.com')
Ciao,
Marc 'BlackJack' Rintsch
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