"Jorgen Bodde" <[EMAIL PROTECTED]> ha scritto nel messaggio news:[EMAIL PROTECTED] > Hi All, > > Now that I am really diving into Python, I encounter a lot of things > that us newbies find difficult to get right. I thought I understood > how super() worked, but with 'private' members it does not seem to > work. For example; > > >>> class A(object): > ... def __baseMethod(self): > ... print 'Test' > > Deriving from A, and doing; > > >>> class D(A): > ... def someMethod(self): > ... super(A, self).__baseMethod() > ... print 'test3' > > Will not work;
if you type >> dir(A) you'll get a method named _A__baseMethod >From the documentation: Private name mangling: When an identifier that textually occurs in a class definition begins with two or more underscore characters and does not end in two or more underscores, it is considered a private name of that class. Private names are transformed to a longer form before code is generated for them. The transformation inserts the class name in front of the name, with leading underscores removed, and a single underscore inserted in front of the class name. For example, the identifier __spam occurring in a class named Ham will be transformed to _Ham__spam. This transformation is independent of the syntactical context in which the identifier is used. If the transformed name is extremely long (longer than 255 characters), implementation defined truncation may happen. If the class name consists only of underscores, no transformation is done. Enrico -- http://mail.python.org/mailman/listinfo/python-list
