Scott wrote: > Now I know list is a bad name, but for the sake of arguement lets assume its > not a built in sequence>
It's easier to use another name, than writing all that parragraph, ;) > I understand all that. What I don't understand is why all the documentation > I see says, "When removing a specific element from a list using pop() it > must be in this format: list.pop([i]). You're reading it everywhere because it's the correct syntax, ;) > At first I took that to mean that list.pop(i) would return some type of > error, but it doesn't. "i" is enclosed in square brackets because it's optional. So, list.pop(i) is a correct way to call it, as correct as list.pop(). Take note that list.pop([i]) is *not* the correct way to call it. I assume you're getting confused by the [], asuming that those means a list. No. Take a look here: http://www.python.org/doc/current/lib/typesseq-mutable.html As you see there, when an iterable is needed, it just named different, syntax do not use brackets to mean "list". > Now I'm not stupid enough to believe that I'm the first to try: >>>>list = ['this', 'is', 'an', 'example'] >>>>list.pop(1) > and have it return the desired effect of: > 'is' >>>>list > ['this', 'an', 'example'] But try this also: >>> l = ['this', 'is', 'an', 'example'] >>> l.pop([2]) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: an integer is required Regards, -- . Facundo . Blog: http://www.taniquetil.com.ar/plog/ PyAr: http://www.python.org/ar/ -- http://mail.python.org/mailman/listinfo/python-list
