On Tue, 2007-04-10 at 21:23 -0700, Paul Rubin wrote: > Carsten Haese <[EMAIL PROTECTED]> writes: > > You have a point. Here is my revised solution: > > > > assert current_player in p > > opponents = tuple(x for x in p if x is not current_player) > > Still wrong on two counts. First, assert is a no-op if optimization > is turned on.
Right. I already responded to this when Bjorn made the same objection. Please try to keep up. > Second, your version returns a different result from > the original if current_player occurs in p more than once. First of all, in the use case we're talking about, current_player shouldn't occur in p more than once. And if it did, is it really reasonable to demand that that player be their own opponent? I don't think so. So yes, the result is different because it's correct, and the tuple.index-based solution is actually incorrect in this case. -Carsten -- http://mail.python.org/mailman/listinfo/python-list
