In article <[EMAIL PROTECTED]>,
"[EMAIL PROTECTED]" <[EMAIL PROTECTED]> wrote:
> On Apr 8, 12:29�pm, Lorenzo <[EMAIL PROTECTED]> wrote:
> > In article <[EMAIL PROTECTED]>,
> >
> >
> >
> >
> >
> > "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> wrote:
> > > On Apr 8, 11:34?am, Lorenzo Thurman <[EMAIL PROTECTED]>
> > > wrote:
> > > > I have tuple which hold a string in tup[0]. I want to get a slice of
> > > > that string. I thought I would do something like:
> > > > tup[0][start:end]
> > > > But this fails.
> >
> > > No, it doesn't.
> >
> > > >>> a = ('abcdefg','hijkl')
> > > >>> a[0]
> > > 'abcdefg'
> > > >>> a[0][1:2]
> > > 'b'
> >
> > > > How do I go about it?
> >
> > > Do it correctly. Post your actual example that fails
> > > and the related error message. Possibnly your indexes
> > > were out of range.
> >
> > > > I googled this and found a couple
> > > > of references, but no solution.
> >
> > > Well, there wouldn't be a solution to a non-existent
> > > problem, would there?
> >
> > > > TIA
> >
> > Here's the code:
> >
> > elapsedTime = mydata[1]
> > index = elapsedTime.find("real")
> > # the index will have a value 0f 110
> > totaltime = elapsedTime[index:]
> > # instead of this returning a shortened html string, i only
> > # get the left angle bracket '<'
>
> This implies that '<' is the 111th character (counting
> from 0) and that it is the last character since you used
> [index:].
>
> Print out the entire string elapsedTime, count from
> 0 to the characters you want and see if you have the
> correct index numbers (verify them).
>
>
> >
> > --
> > "My Break-Dancing days are over, but there's always the Funky Chicken"
> > --The Full Monty
Oops! I sent the wrong piece of code. The above is actually the work
around which actually works. The bad code is this:
index = mydata[0].find("real")
elapsedTime = mydata[0][index:]
My apologies, but this is what fails.
--
"My Break-Dancing days are over, but there's always the Funky Chicken"
--The Full Monty
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