Hi all, I'm trying to extract zip file (containing an xml file) from an email so I can process it. But I'm running up against some brick walls. I've been googling and reading all afternoon, and can't seem to figure it out.
Here is what I have so far. p = POP3("mail.server.com") print p.getwelcome() # authentication, etc. print p.user("USER") print p.pass_("PASS") print "This mailbox has %d messages, totaling %d bytes." % p.stat() msg_list = p.list() print msg_list if not msg_list[0].startswith('+OK'): # Handle error exit(1) for msg in msg_list[1]: msg_num, _ = msg.split() resp = p.retr(msg_num) if resp[0].startswith('+OK'): #print resp, '=======================\n' #extract message body and attachment. parsed_msg = email.message_from_string('\n'.join(resp[1])) payload= parsed_msg.get_payload(decode=True) print payload #doesn't seem to work else: pass# Deal with error retrieving message. How do I: a) retrieve the body of the email into a string so I can do some processing? (I can get at the header attributes without any trouble) b) retrieve the zip file attachment, and unzip into a string for xml processing? Thanks so much for your help! Erik -- http://mail.python.org/mailman/listinfo/python-list