7stud wrote: > On Apr 3, 3:53 pm, "bahoo" <[EMAIL PROTECTED]> wrote: > > > target = "0024" > > > l = ["0024", "haha", "0024"] > > > > > > > for index, val in enumerate(l): > > > if val==target: > > > del l[index] > > > > > print l > > > > This latter suggestion (with the for loop) seems to be buggy: if there > > are multiple items in the list "l" equal to "target", then only the > > first one will be removed! > > > > Thanks anyways. > > Prove it. here's something:
>>> l = ["0024", "haha", "0024", "0024", "sfs"] >>> target = "0024" >>> for index, val in enumerate(l): ... print "index: " , index , "value: " , val ... del l[index] ... print "after del: " , l ... index: 0 value: 0024 after del: ['haha', '0024', '0024', 'sfs'] index: 1 value: 0024 after del: ['haha', '0024', 'sfs'] index: 2 value: sfs after del: ['haha', '0024'] >>> l ['haha', '0024'] -- http://mail.python.org/mailman/listinfo/python-list
