On Apr 3, 1:49 pm, [EMAIL PROTECTED] wrote:
> On Apr 3, 1:31 pm, "Matimus" <[EMAIL PROTECTED]> wrote:
>
> > It depends on your application, but a 'set' might really be what you
> > want, as opposed to a list.
>
> > >>> s = set(["0024","haha","0024"])
> > >>> s
>
> > set(["0024","haha"])>>> s.remove("0024")
> > >>> s
>
> > set(["haha"])
>
> If you want, you can also loop over the list, like so:
>
> counter = 0
> your_list = ["0024","haha","0024"]
> for i in your_list:
> if i == '0024':
> your_list.pop(counter)
> counter += 1
>
> Mike
This method doesn't work.
>>> li = list('hello larry')
>>> count = 0
>>> for i in li:
... if i=='l':
... li.pop(count)
... coun += 1
...
'l'
'l'
>>> l
['h', 'e', 'l', 'o', ' ', 'a', 'r', 'r', 'y']
because the indexes change as you pop, it gets some of them but not
all.
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