Hi There,
Here's the full code, if it helps:
"""
Takes a list of filenames via standard input and uploads them to
Amazon S3.
Requires S3.py:
http://developer.amazonwebservices.com/connect/entry.jspa?externalID=134&categoryID=47
Usage:
cd /directory/with/media/files/
find | grep -v ".svn" | python /path/to/update_s3.py
Before you use this, change the aws_access_key_id, aws_secret_key and
bucket_name variables at the top of the file.
You can run this multiple times on the same files -- it'll just
override the
files that were in your S3 account previously.
"""
import mimetypes
import os
import settings
import os.path
import sys
os.environ['DJANGO_SETTINGS_MODULE'] = 'settings'
from custom_filters import filename_slugify
import S3
import settings
aws_access_key_id = settings.AWS_ACCESS_KEY_ID
aws_secret_key = settings.AWS_SECRET_KEY
def update_s3(bucket_name=bucket_name):
conn = S3.AWSAuthConnection(aws_access_key_id, aws_secret_key)
for line in sys.stdin:
filename = os.path.normpath(line[:-1])
if ((filename == '.' or not os.path.isfile(filename)) or
(filename.find('ds_store') >= 0)):
continue # Skip this, because it's not a file.
print "Uploading %s" % filename_slugify(filename)
filedata = open(filename, 'rb').read()
content_type = mimetypes.guess_type(filename)[0]
if not content_type:
content_type = 'text/plain'
conn.put(bucket_name, filename_slugify(filename),
S3.S3Object(filedata),
{'x-amz-acl': 'private', 'Content-Type': content_type})
if __name__ == "__main__":
bucket_name = raw_input('Name of the bucket you wish the files to be
placed into? ')
update_s3()
Basically I pipe some files into the script - so would this cause a
linebreak?
--
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