On Apr 2, 4:20 pm, Ernesto García García <[EMAIL PROTECTED]> wrote: > Hi experts, > > How would you do this without the more and more indenting cascade of ifs?: > > match = my_regex.search(line) > if match: > doSomething(line) > else: > match = my_regex2.search(line) > if match: > doSomething2(line) > else: > match = my_regex3.search(line) > if match: > doSomething3(line) > > etc. > > Thanks in advance and regards, > Ernesto
You might be able to use "guard clauses": http://www.refactoring.com/catalog/replaceNestedConditionalWithGuardClauses.html match = my_regex.search(line) if match: doSomething(line) return match = my_regex2.search(line) if match: doSomething2(line) return But if all of the blocks contain the same code like they do in your example, you're better off using the solutions provided by Wojciech Muła and Duncan Booth, because they abstract away the repetition. -- http://mail.python.org/mailman/listinfo/python-list
