On Apr 1, 9:24 pm, "7stud" <[EMAIL PROTECTED]> wrote:
> On Apr 1, 7:43 pm, Michael Hoffman <[EMAIL PROTECTED]> wrote:
>
>
>
> > asdf1234234 wrote:
> > > -a.py-
> > > import b
>
> > > class A:
> > > def __init__(self):
> > > pass
> > > def my_method(self):
> > > var = 1
> > > self.var = 2
> > > b.set_var(self)
> > > print var
> > > print self.var
>
> > > my_a = A()
> > > my_a.my_method()
>
> > > -b.py-
> > > def set_var(self):
> > > var = 2
> > > self.var = 2
>
> > > I want both var and self.var to be 2 at the end. Is there anything I
> > > can pass to set_var() that will give it access to the variables in
> > > my_method() like I can use self for the variables in the class A?
>
> > I hope there isn't a way to do this that simply. :) Why do you want to
> > do this, or is it idle curiosity? There is almost surely a better way to
> > solve your underlying problem.
>
> > You can *read* your caller's local variables (either pass locals() as an
> > argument or use inspect to get the frame locals), but writing to this
> > dictionary has undefined behavior.
> > --
> > Michael Hoffman
>
> class A(object):
> def early_parse(self):
> self.result1 = eval("10+5")
> def later_parse(A_obj):
> A_obj.result2 = eval("20*2")
>
> a = A()
> a.early_parse()
> later_parse(a)
> print a.result1
> print a.result2
Oops. That def should be:
def later_parse(A_obj):
A_obj.result2 = A_obj.result1 + eval("20*2")
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