On Apr 1, 7:51 am, "Pierre Quentel" <[EMAIL PROTECTED]> wrote: > > Four groups of firefighters (group1, group2, group3, group4). Each > > group works a 24 hr shift. So group1 works April 1, group2 works April > > 2, group3 works April 3, group4 works April 4, group 1 works April 5, > > etc. It just keeps rolling like this forever into next year, etc. > > > I need to come up with a methodology for the following: > > > If given a date, find out what group is working on that date. > > Hello, > > You can use method datetime.date.toordinal() : > > from datetime import date > start = date(2007,4,1) # Arpil 1, 2007 > > def group(_date): > return (date.toordinal(_date)-date.toordinal(start)) % 4
... whose possible outcomes are (0, 1, 2, 3) whereas the groups are numbered 1 to 4. However I'm sure the OP can make the necessary adjustment :-) > > print group(date(2007,4,15)) > > Regards, > Pierre -- http://mail.python.org/mailman/listinfo/python-list
