On Mar 29, 8:49 am, [EMAIL PROTECTED] (Alex Martelli) wrote:
> Ben Finney <[EMAIL PROTECTED]> wrote:
>
> ...
>
> > That's not the only case though. What do you expect to be returned for
> > an input of ["eggs", "beans", "beans", "eggs", "spam"] ?
>
> > Assuming you want *a* mode value, and any one will do (e.g. any of
> > "spam", "eggs" or "beans" is okay), I'd write it this way as a first
> > guess:
>
> > >>> foo = ["spam", "eggs", "spam", "spam", "spam", "beans", "eggs"]
> > >>> counts = [(foo.count(val), val) for val in set(foo)]
> > >>> counts
> > [(2, 'eggs'), (1, 'beans'), (4, 'spam')]
> > >>> sorted(counts)[-1]
> > (4, 'spam')
> > >>> sorted(counts)[-1][1]
> > 'spam'
>
> A bit more directly:
>
> >>> foo = ["spam", "eggs", "spam", "spam", "spam", "beans", "eggs"]
> >>> max(foo, key=foo.count)
>
> 'spam'
>
> Alex
This doesn't call foo.count for duplicate entries by keeping a cache
>>> foo = ["spam", "eggs", "spam", "spam", "spam", "beans", "eggs"]
>>> def cachecount(x, cache={}):
... return cache.setdefault(x, foo.count(x))
...
>>> max(foo, key=cachecount)
'spam'
>>> cachecount.func_defaults
({'eggs': 2, 'beans': 1, 'spam': 4},)
>>>
- Paddy.
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