Roose wrote:
I need this a lot: a one line way to do a n-ary and or 'or'.
e.g.,
result = True
for x in L:
if not boolean_function(x):
result = False
or
reduce(operator.__and__, [boolean_function(x) for x in L)
Can you use itertools?
py> def boolfn(x):
... print "boolfn: %r" % x
... return bool(x)
...
py> True in itertools.imap(boolfn, ['a', '', 'b'])
boolfn: 'a'
True
py> True in itertools.imap(boolfn, ['', '', ''])
boolfn: ''
boolfn: ''
boolfn: ''
False
py> False in itertools.imap(boolfn, ['a', '', 'b'])
boolfn: 'a'
boolfn: ''
True
py> False in itertools.imap(boolfn, ['a', 'a', 'b'])
boolfn: 'a'
boolfn: 'a'
boolfn: 'b'
False
It even shortcircuits when appropriate.
Steve
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