This works much better, aside from the fact that it does'nt work for
the std dictionary. the letters used from here stay the same. that
dictionary looks like this:
std = {
"A":"Z",
"Z":"A",
"B":"Y",
"Y":"B",
"C":"X",
"X":"C",
"E":"V",
"V":"E",
"H":"S",
"S":"H",
"M":"N",
"N":"M"
}
what could be causing this?
i did figure out that if you reverse the k,v you are able to get it but
that doesn't turn up the results i need
def proc(text):
result = []
for word in text:
for k, v in replacements:
word = word.replace(v,k) #here i reversed them
result.append(word)
return ''.join(result)
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