On Mar 16, 3:51 pm, Shane Geiger <[EMAIL PROTECTED]> wrote: > lines = open('/tmp/foo.py', > "r").read().splitlines() > > > previous_line = > '' > > > for line in > lines: > > > if "foo" in > line: > > > print "found foo in the current line. The previous line is: " > + > previous_line > > previous_line = > line > > > > > > > Qilong Ren wrote: > > Hi,all > > > I am new to this list. And I am glade I am here. > > I have a question. I need to do some text processing. I need to read > > from a file line by line. If some line is met with some condition, the > > previous line needs some modification. How to get the info of the > > previous line? > > > Thanks! > > Qilong > > > ------------------------------------------------------------------------ > > Never miss an email again! > > Yahoo! Toolbar > > <http://us.rd.yahoo.com/evt=49938/*http://tools.search.yahoo.com/toolb...> > > alerts you the instant new Mail arrives. Check it out. > > <http://us.rd.yahoo.com/evt=49937/*http://tools.search.yahoo.com/toolb...> > > -- > Shane Geiger > IT Director > National Council on Economic Education > [EMAIL PROTECTED] | 402-438-8958 | http://www.ncee.net > > Leading the Campaign for Economic and Financial Literacy > > sgeiger.vcf > 1KDownload- Hide quoted text - > > - Show quoted text -
If the list is not long, zip the lines together in pairs: lines = """ test1 test2 foo test3 test4 """.split("\n") for prev,curr in zip(lines[:-1],lines[1:]): if "foo" in curr: break else: prev = "<not found>" print "line before foo is:", prev prints: line before foo is: test2 -- Paul -- http://mail.python.org/mailman/listinfo/python-list