"Steven D'Aprano" <[EMAIL PROTECTED]> wrote:

> 
> Consider the distance between each paid of consecutive poles. The sum of
> the distances must add up to the distance from the first to the last, and
> if there are two fixed poles plus five in between, there are five
> distances.

No there are six distances - the fifth pole has to fit in the same hole as the 
last fixed one for there to be five.

- Hendrik

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