On 12 Mar 2007 16:13:51 -0700, Henrik Lied <[EMAIL PROTECTED]> wrote:
>> I'm trying to create a video uploading service (just to learn). The >> system is mostly based on Django, but the question I'm looking an >> answer for is more related to Python. En Tue, 13 Mar 2007 06:57:33 -0300, rishi pathak <[EMAIL PROTECTED]> escribió: > You can do something like this: > pid = os.fork() I don't think it's a good idea, the running process is Django, not a script. To the OP: I think the question *is* a Django question. You could launch the external process, finish the current request and redirect to another location; in that page you set a refresh to itself, and show the current status "somehow" depending on how your external process can report its progress. The details on how to do that, or even if that way is a good approach at all, depend on Django. -- Gabriel Genellina -- http://mail.python.org/mailman/listinfo/python-list
