On Mar 13, 2:42 pm, Paul Rubin <http://[EMAIL PROTECTED]> wrote: > If I can decipher your Ruby example (I don't know Ruby), I think you > want: > > for name,contact in contacts.iteritems(): > if re.search('search', name): > print contact > > If you just want to filter the dictionary inside an expression, you > can use a generator expression: > > d = ((name,contact) for (name,contact) in contacts.iteritems() \ > if re.search('search', name)) > > print '\n'.join(d) # prints items from filtered dict, one per line > > Note that d is an iterator, which means it mutates when you step > through it.
Paul - You're exactly on the mark. I guess I was just wondering if your first example (that is, breaking the if statement away from the iteration) was preferred rather than initially filtering and then iterating. However, you're examples make a lot of sense are are quite helpful. Thanks, Drew -- http://mail.python.org/mailman/listinfo/python-list
