On 13 Mar, 06:52, "Amit Khemka" <[EMAIL PROTECTED]> wrote:
> On 3/13/07, Astan Chee <[EMAIL PROTECTED]> wrote:
>
> > I have a string in this format "DD/MM/YYY" for example:
> > tdate = "18/01/1990"
> > and Im trying to convert this to epoch time, can anyone help?
>
> import calendar
> t = map(int,tdate.split('/'))
> epochs = calendar.timegm((t[2], t[1], t[0], 0, 0, 0))
You can also use strptime:
import time
t = time.strptime("18/01/1990", "%d/%m/%Y")
epochs = calendar.timegm(t)
Whilst timegm is a hidden gem in the calendar module, it is actually
based on a library function on certain platforms. I've submitted a
patch to add a platform-independent version to the time module -
requests to add such a function previously led only to documentation
changes, I believe. (I think that many people regard mktime as doing
the work that only timegm actually accomplishes, so it's an important
addition.)
> > Im also trying to convert that epoch time to the string format
> > previously. Can anyone help this one too?
>
> import time
> time.ctime(epochs)
Note that ctime makes a string in a particular format (not the
original one, though) from the local time. It might be better to use
strftime instead:
import time
time.strftime("%d/%m/%Y", epochs)
Paul
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