Hi all, I'm trying to get some ideas on the best way to do this.
In this particular coding snippet, I was thinking of creating a dictionary of file objects and file names. These would be optional files that I could open and parse. At the end, I would easily close off the files by iterating through the dictionary.
---< CODE FOLLOWS >--- optionalfiles = {fileAreaCode: "areacode.11", fileBuild: "build.11"}
# Try to see if optional file exists, if so, open. try: for key, optionalFile in optionalFiles.iteritems(): key = open(optionalFile, "r") except IOError: key = False
...
# Close optionally open files for key, optionalFile in optionalFiles.iteritems(): if optionalFile: print "Closing: %s" % optionalFile key.close()
---< END CODE >---
My questions are:
Is this even possible in a dictionary to have a key of a file object?
If so, how do I initialise an empty file object? I mean, something along the lines of:
fileAreaCode = open("", "r")
If not, any suggestions on achieving openning optional files in a loop? Otherwise I'm stuck with:
---< BEGIN >---
# Optional input files try: fileAreaCode = open("areacode.11", "r") except: fileAreaCode = False
try: fileBuild = open("build.11", "r") except: fileBuild = False
...
# Close files for optionalFile in [fileAreaCode, fileBuild]: if optionalFile: print "Closing: %s" % str(optionalFile) optionalFile.close()
---< END >---
Thanks, Julian -- http://mail.python.org/mailman/listinfo/python-list