Thanks,
I've tried the StringIO option as follows:
=================================
img = Image.open('/some/path/img.jpg')
img.thumbnail((640,480))
file = StringIO, StringIO()
img.save(file, 'JPEG')
=================================
But it gives me:
=================================
exceptions.TypeError Traceback (most
recent call last)
C:\Python24\lib\site-packages\PIL\Image.py in save(self, fp, format,
**params)
1303
1304 try:
-> 1305 save_handler(self, fp, filename)
1306 finally:
1307 # do what we can to clean up
C:\Python24\lib\site-packages\PIL\JpegImagePlugin.py in _save(im, fp,
filename)
407 )
408
--> 409 ImageFile._save(im, fp, [("jpeg", (0,0)+im.size, 0,
rawmode)])
410
411 def _save_cjpeg(im, fp, filename):
C:\Python24\lib\site-packages\PIL\ImageFile.py in _save(im, fp, tile)
464 bufsize = max(MAXBLOCK, im.size[0] * 4) # see RawEncode.c
465 try:
--> 466 fh = fp.fileno()
467 fp.flush()
468 except AttributeError:
TypeError: descriptor 'fileno' of 'file' object needs an argument
=================================
It looks similar to the code in Sparklines except for the fact that
the latter creates an Image from scratch.
2B
> Saving the image, in a
> format your client understands, to a file like object like
> StringIO.StringIO is an easy path to take.
>
> Sparklines shows this in action:
>
> http://bitworking.org/projects/sparklines/
>
> max
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