John Henry wrote: > Or more precisely: > > round(0.014999999999999999,2)
No, that *won't* solve the problem. Using a slightly different example, >>> x = 1.5 * 0.1 >>> x 0.15000000000000002 >>> round(x, 2) 0.14999999999999999 The problem is that floats are stored internally in binary, not decimal, and numbers like 0.1 and 0.01 have no exact representation as a binary float. Using round() doesn't help, because the result is still a binary float, and the result you're after still can't be represented. The best you can do is to *display* it rounded to the number of digits you want using formatting, e.g. >>> "%.2f" % x '0.15' Alternatively, use the Decimal module, which stores numbers as decimal and does arithmetic in ways that will match your calculator. It's slower, though. -- Greg -- http://mail.python.org/mailman/listinfo/python-list
