> Well, you'd have to define the function inside the sortMoves function, as > it is where the variables exists. > > def sortMoves(board, table, ply, moves): > def sortKey(move): > return getMoveValue(board, table, ply, move) > moves.sort(key=sortKey, reverse=True) return moves > > Wouldn't that make it create the callable at each call?
Yes, it does. But it's only created _once_ per sortMoves-call, and afterwards doesn't affect performance. And no, it's not slower than you lambda version - they _should_ be equally fast, if not it's neglible. And also doesn't affect sorting-performance. Diez -- http://mail.python.org/mailman/listinfo/python-list
