On Mar 2, 3:08 am, "MooMaster" <[EMAIL PROTECTED]> wrote: > Hey guys, I'm trying to do some black magic voodoo and it's a little > late, so forgive me if this question seems obvious or has been asked > before. I tried doing a search on context objects and didn't find > anything that popped out, and I'm too tired to keep digging. > > I'm making a little program that is trying to do weird and sexy things > by fully leveraging the power of all the built-in beauty of Python. I > was trying to play around with the new features added into Python 2.5, > and ran into an unexpected issue...check this out: > > >>> moo = lambda x, y : decimal.Context(3).sqrt(decimal.Context(3).power(x,2) > >>> + decimal.Context(3).power(y,2)) > >>> moo > > <function <lambda> at 0x02CD0EB0>>>> row = [1,2,3,4,5] > >>> weight_vector = .00556 > >>> moo(sum(row), weight_vector) > > Traceback (most recent call last): > File "<pyshell#5>", line 1, in <module> > moo(sum(row), weight_vector) > File "<pyshell#1>", line 1, in <lambda> > moo = lambda x, y : > decimal.Context(3).sqrt(decimal.Context(3).power(x,2) + > decimal.Context(3).power(y,2)) > File "C:\Python25\lib\decimal.py", line 2662, in power > return a.__pow__(b, modulo, context=self) > TypeError: wrapper __pow__ doesn't take keyword arguments > > I have no idea what keyword argument is getting passed to __pow__, > anyone know what's going on? > > This should compute sqrt(5^2 + 3^2)
Oh sorry, ignore that last line, that was a copy/paste from another example I forgot to remove...OBVIOUSLY it's going to compute something else, that's not what I'm asking about...stupid late night hacking! XD -- http://mail.python.org/mailman/listinfo/python-list
