[EMAIL PROTECTED] writes:
> While it should be easy for me to get what I need from a list, it's
> proving to be more difficult than I expected.
>
> I start with this list:
>
> [ 6.24249034e-01+0.j 5.11335982e-01+0.j 3.67333773e-01+0.j
> 3.01189122e-01+0.j 2.43449050e-01+0.j 1.82948476e-01+0.j
> 1.43655139e-01+0.j 9.91225725e-02+0.j]
That's not correct syntax for a list. I assume, then, that it's not
actual code from your program.
> and I want a list of floats of only the first 6 digits for each value.
You don't get to choose how many digits are represented in a float
value; that's a property of the underlying floating-point
implementation, and indeed will change depending on the actual value
(since a float is a *binary* representation of a number, not decimal).
Perhaps you are looking for the Decimal type:
<URL:http://docs.python.org/lib/module-decimal.html>
> for i in listname:
> print i
>
> I get this:
> [each item printed separately]
>
> I know it's embarrassingly simple, but the correct syntax eludes
> my inexperienced mind. What I want is a list [0.62424, 0.51133, ...]
> so that I can normalize those values.
You can create a new list from any sequence value by using the
constructor for the list type:
>>> old_sequence = [12, 34, 56]
>>> new_list = list(old_sequence)
>>> new_list[0]
12
As for making a list containing different values (e.g. Decimal
values), you might want a list comprehension:
>>> from decimal import Decimal
>>> old_sequence = [12, 34, 56]
>>> new_list = [Decimal(value) for value in old_sequence]
>>> new_list[0]
Decimal("12")
--
\ "I may disagree with what you say, but I will defend to the |
`\ death your right to mis-attribute this quote to Voltaire." -- |
_o__) Avram Grumer, rec.arts.sf.written, May 2000 |
Ben Finney
--
http://mail.python.org/mailman/listinfo/python-list
