Ziga Seilnacht wrote: > The second example uses your approach and is a bit more cumbersome, > but still works. Could you post your current version of the code? > I don't understand where your problem could be.
I think, there's no need to. Now I understand :) > if (!PyArg_ParseTuple(args, "Oid", &coord, > &iteration_number, &bailoutsquare)) There was no ampersand in my version before coord. I thought that as coord is already a pointer, PyArg_ParseTuple will want it, not the pointer to the pointer. Now it works, but I will of course change it to get the simpler parenthesised version as in your Example 1. Great thanks :D zefciu -- http://mail.python.org/mailman/listinfo/python-list
