On Feb 22, 3:05 am, Paul Rubin <http://[EMAIL PROTECTED]> wrote: > [EMAIL PROTECTED] writes: > > Lists say I have the following tuple - > > t1 = ("ONE","THREE","SIX") > > t2 = ("ONE","TWO","THREE") > > t3 = ("TWO","FOUR","FIVE","SIX") > > t4 = ("TWO",) > > t5 = ("TWO","FIVE") > > > What I want to do is return true if any member of tuple t1 is found in > > the remaining tuples. > > Convert them into sets and use the set intersection (&) operator, > then convert to bool to represent whether the intersection is empty. > > print bool(set(t1) & set(t2)) > print bool(set(t1) & set(t3)) > print bool(set(t1) & set(t4)) > print bool(set(t1) & set(t5))
A step further: use union to make a superset of t2-tN, then use & on this superset. setlist = [t2,t3,t4,t5] superset = reduce(set.union, map(set,setlist) ) print bool(t1 & superset) -- Paul -- http://mail.python.org/mailman/listinfo/python-list
