> Without looking into the details -- the (subclass of) type is meant to be > the class of the class, or the other way round, your normal classes are > instances of (a subclass of) type. You determine the factory Python uses to > make a class by adding > > __metaclass__ = factory > > to the class body, so you'll probably end with something like > > class ProducerHandlerType(type): > # your code > > class A: > __metaclass__ = ProducerHandlerType > > The subclasses of A will now invoke your customised metaclass machinery. > Thanks, I missed that. I added the __metaclass__ line and it worked like a charm.
Laszlo -- http://mail.python.org/mailman/listinfo/python-list
