En Fri, 16 Feb 2007 23:36:26 -0300, vithi <[EMAIL PROTECTED]> escribió:
> I am trying to launch an application. When I try like that
> When I try like that Excel is opening
> import win32com.client
> object = win32com.client.Dispatch("Excel.Application")
> object.Visible = 1
>
> But when I try my application which is QeepIt.exe
> which is in the c:\ drive it is not running
> Any body tell me how to give path to open an exectable application in
> Dispatch modules
> I try like that
> object = win32com.client.Dispatch("c:\Folder\QeepIt.exe")
> It give an error.
The above code is used to launch a COM server registered under the name
"Excel.Application" and then control it. If you don't know what a COM
server is, surely your application can't be used this way.
For launching another program, perhaps sending it some text, and capturing
its output, look at the subprocess module. If you are only interested in
executing it, with no additional communication, os.system() may be enough.
--
Gabriel Genellina
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