Lance Hoffmeyer wrote:
> I have a search:
>
> VAR = re.search("PROVEN.*?\n[\sA-Za-z\(\)\/\-]+\d(.*?)\n.*?" , pcpT9, re.S
> ).group(1) #.split()[1]
>
> that does not match (sometimes it will and sometimes it will not match)
>
> Traceback (most recent call last):
> File "P:\Burke\TRACKERS\Ortho-McNeil\Automation\Wave3\test.py", line 53,
> in ?
> VAR = re.search("PROVEN.*?\n[\sA-Za-z\(\)\/\-]+\d(.*?)\n.*?" , pcpT9,
> re.S ).group(1) #.split()[1]
> AttributeError: 'NoneType' object has no attribute 'group'
>
>
> Is there a way in python to make this "non" match equal a value (say,
> "0")?
match = re.search(...)
if match:
value = match.group(1)
else:
value = default
Wrap that into a function and you can use it inside a list comprehension.
> This one line is actually a series of searches
>
> Reasons = ["EFFICACY","EFFECTIVE","WORKS
> QUICKLY","PROVEN","SAFETY","LITTLE","WELL"," BETTER","SAMPLES"] #
> Reasons(29)
> VAR = [re.search(r"%s.*?\n[\sA-Za-z\(\)\/\-]+\d(.*?)\n.*?" % i, pcpT9,
> re.S ).group(1) for i in Reasons ] #.split()[1]
>
> and one of the items in the array may or may not be present.
How about a slightly different approach (untested):
r = re.compile(r"(%s).*?\n[\sA-Za-z\(\)\/\-]+\d(.*?)\n.*?" %
"|".join(reasons), re.S)
groups = dict(m.groups() for m in r.finditer(pcpT9))
VAR = [groups.get(reason, "0") for reason in reasons]
I recommend that you don't create the VAR list and use groups directly.
If you are using Python 2.5 you can replace the builtin dict with a
collections.defaultdict.
Peter
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