On Feb 11, 5:13 am, Samuel Karl Peterson <[EMAIL PROTECTED]> wrote: > "Johny" <[EMAIL PROTECTED]> on 10 Feb 2007 05:29:23 -0800 didst step > forth and proclaim thus: > > > I need to find all the same words in a text . > > What would be the best idea to do that? > > I make no claims of this being the best approach: > > ==================== > def findOccurances(a_string, word): > """ > Given a string and a word, returns a double: > [0] = count [1] = list of indexes where word occurs > """ > import re > count = 0 > indexes = [] > start = 0 # offset for successive passes > pattern = re.compile(r'\b%s\b' % word, re.I) > > while True: > match = pattern.search(a_string) > if not match: break > count += 1; > indexes.append(match.start() + start) > start += match.end() > a_string = a_string[match.end():] > > return (count, indexes) > ==================== > > Seems to work for me. No guarantees. >
More concisely: import re pattern = re.compile(r'\b324\b') indices = [ match.start() for match in pattern.finditer(target_string) ] print "Indices", indices print "Count: ", len(indices) -- Cheers, Steven -- http://mail.python.org/mailman/listinfo/python-list
