Hi Jandre,
Your code is treating the directory as a file and trying to open it and read
its bytes to zip them. You'll need to differentiate between files and
directories.
You'll need to check out the Zip module to see how it expects files that
should be nested within folders. I believe you'll need to set the archive
name for the nested files to something like \\temp\\file.ext etc.
-Josh
On 4 Feb 2007 11:42:23 -0800, Jandre <[EMAIL PROTECTED]> wrote:
On Feb 1, 9:39 pm, Larry Bates <[EMAIL PROTECTED]> wrote:
> Jandre wrote:
> > Hi
>
> > I am a python novice and I am trying to write a python script (most of
> > the code is borrowed) to Zip a directory containing some other
> > directories and files. The script zips all the files fine but when it
> > tries to zip one of the directories it fails with the following
> > error:
> > "IOError: [Errno 13] Permission denied: 'c:\\aaa\\temp'"
>
> > The script I am using is:
>
> > import zipfile, os
>
> > def toZip( directory, zipFile ):
> > """Sample for storing directory to a ZipFile"""
> > z = zipfile.ZipFile(
> > zipFile, 'w', compression=zipfile.ZIP_DEFLATED
> > )
> > def walker( zip, directory, files, root=directory ):
> > for file in files:
> > file = os.path.join( directory, file )
> > # yes, the +1 is hacky...
> > archiveName = file[len(os.path.commonprefix( (root,
> > file) ))+1:]
> > zip.write( file, archiveName, zipfile.ZIP_DEFLATED )
> > print file
> > os.path.walk( directory, walker, z )
> > z.close()
> > return zipFile
>
> > if __name__ == "__main__":
> > toZip( 'c:\\aaa', 'c:\\aaa\\test.zip' )
>
> > I have tried to set the permissions on the folder, but when I check
> > the directory permissions it is set back to "Read Only"
>
> > Any suggestions?
>
> > Thanks
> > Johan Balt
>
> Couple of quick suggestions that may help:
>
> 1) don't use 'file' as a variable name. It will mask
> the builtin file function. If it hasn't bitten you before
> it will if you keep doing that.
>
> 2) If you put the target .zip file in the directory you are
> backing what do you expect the program to do when it comes
> to the file you are creating as you walk the directory? You
> haven't done anything to 'skip' it.
>
> 3) Your commonprefix and +1 appears to result in same
> information that the easier to use os.path.basename()
> would give you. Double check me on that.
>
> I don't see anything that references C:\\aaa\temp in your
> code. Does it exist on your hard drive? If so does it
> maybe contain temp files that are open? zipfile module
> can't handle open files. You must use try/except to
> catch these errors.
>
> Hope info helps.
>
> -Larry
Thank you Larry.
I've changed the code as epr your advice. The code is now:
import zipfile, os
def toZip( directory, zipFile ):
"""Sample for storing directory to a ZipFile"""
z = zipfile.ZipFile(
zipFile, 'w', compression=zipfile.ZIP_DEFLATED
)
def walker( zip, directory, files, root=directory ):
for f in files:
f = os.path.join( directory, f )
archiveName = os.path.basename(f)
zip.write( f, archiveName, zipfile.ZIP_DEFLATED )
print f
os.path.walk( directory, walker, z )
z.close()
return zipFile
if __name__ == "__main__":
toZip( 'c:\\aaa\\', 'c:\\bbb\\test.zip' )
I still get the same error:
Traceback (most recent call last):
File "C:\Python24\Lib\site-packages\pythonwin\pywin\framework
\scriptutils.py", line 310, in RunScript
exec codeObject in __main__.__dict__
File "C:\Python24\Scripts\dirZip.py", line 20, in ?
toZip( 'c:\\aaa\\', 'c:\\bbb\\test.zip' )
File "C:\Python24\Scripts\dirZip.py", line 14, in toZip
os.path.walk( directory, walker, z )
File "C:\Python24\lib\ntpath.py", line 329, in walk
func(arg, top, names)
File "C:\Python24\Scripts\dirZip.py", line 12, in walker
zip.write( f, archiveName, zipfile.ZIP_DEFLATED )
File "C:\Python24\lib\zipfile.py", line 405, in write
fp = open(filename, "rb")
IOError: [Errno 13] Permission denied: 'c:\\aaa\\temp'
c:\\aaa\\temp is a directory in the directory I an trying to zip. I
want to use this script to back up my work once a day and would like
to
keep the directory structure as is. I can zip the files in c:\aaa\tem
fine so I guess that there aren't any open files in the directory.
Any more ideas?
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