On Tue, 30 Jan 2007 15:05:23 +0000, Hugo Ferreira <[EMAIL PROTECTED]> wrote:
>Hi there,
>
>I have a problem. I'm using calling shutil.copyfile() followed by
>open(). The thing is that most of the times open() is called before
>the actual file is copied. I don't have this problem when doing a
>step-by-step debug, since I give enough time for the OS to copy the
>file, but at run-time, it throws an exception.
>
>Is there anyway to force a sync copy of the file (make python wait for
>the completion)?
shutil.copyfile() _is_ synchronous. Check out the source:
def copyfileobj(fsrc, fdst, length=16*1024):
"""copy data from file-like object fsrc to file-like object fdst"""
while 1:
buf = fsrc.read(length)
if not buf:
break
fdst.write(buf)
def copyfile(src, dst):
"""Copy data from src to dst"""
if _samefile(src, dst):
raise Error, "`%s` and `%s` are the same file" % (src, dst)
fsrc = None
fdst = None
try:
fsrc = open(src, 'rb')
fdst = open(dst, 'wb')
copyfileobj(fsrc, fdst)
finally:
if fdst:
fdst.close()
if fsrc:
fsrc.close()
The problem you are experiencing must have a different cause.
Jean-Paul
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