On Jan 28, 10:58 pm, "NoName" <[EMAIL PROTECTED]> wrote:
> Perl:
> @char=("A".."Z","a".."z",0..9);
> do{print join("",@char[map{rand @char}(1..8)])}while(<>);
>
> !!generate passwords untill U press ctrl-z
>
> Python (from CookBook):
>
> from random import choice
> import string
> print ''.join([choice(string.letters+string.digits) for i in
> range(1,8)])
>
> !!generate password once :(
>
> who can write this smaller or without 'import'?
from random import choice
pwdchars = ''.join(chr(c) for c in range(ord('a'),ord('z')+1)+
range(ord('A'),ord('Z')+1)+
range(ord('0'),ord('9')+1) )
while(True) : print ''.join(choice(pwdchars) for i in range(8))
(Note that you want to use range(8), not range(1,8), since range gives
you the values [a,b) if two arguments are given, or [0,a) if only one
is given, and it appears that you want 8-character passwords.)
But really, there's nothing wrong with using import, and reusing known
good code from the string module is better than reimplementing it in
new code as I have done (less code === fewer opportunities for bugs).
rand is not a built-in as it apparently is in Perl, but random is part
of the core library, so all Python installs will have it available -
likewise for string.
-- Paul
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