Duncan Booth:
> def nsplit(s, sep, n):
> return (s.split(sep) + [""]*n)[:n]
Another version, longer:
from itertools import repeat
def nsplit(text, sep, n):
"""
>>> nsplit("bcsn; 1000001; 1456", ";", 3)
['bcsn', ' 1000001', ' 1456']
>>> nsplit("bcsn; 1000001", ";", 3)
['bcsn', ' 1000001', '']
>>> nsplit("bcsn", ";", 3)
['bcsn', '', '']
>>> nsplit("", ".", 4)
['', '', '', '']
>>> nsplit("ab.ac.ad.ae", ".", 2)
['ab', 'ac', 'ad', 'ae']
"""
result = text.split(sep)
nparts = len(result)
result.extend(repeat("", n-nparts))
return result
if __name__ == "__main__":
import doctest
doctest.testmod()
Bye,
bearophile
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